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123 100

123   100

1 + 2 + 3 + 4 + ⋯ 123 100 Since the only operation inside the brackets is a single sum, we first add 1 1 to 100 100 to get 101 101 4×3−1 2 + 4 × 3 − 1 Solution Applying BODMAS, we 123 100 Calculate the sum of the given series: Given series: 1 , 2 , 3 , 4 , 5 , , 100 The given series is in arithmetic progression

123 100 According to arithmetic progression, natural numbers can be written down as 1, 2, 3, 4, 5, 6, 7, and 8 to 100 A=1; D=1; N=100 Now moving toward the

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